Programming and Algorithm

Example of Algorithm in Real Life

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Washing clothes

Analysis :

Problem : Algorithm of washing clothes with automatic washing machine

Requirement :

Input : Clothes, detergent, softener

Process : Put the clothes into the washing machine then washed

Output : Clothes washed and dried

Algorithm :

1. Plug the washing machine cable into the stop-contact

2. Open the washing machine's top

3. Put clothes into the machine

4. Add detergent and softener

5. Close the machine's top

6. Turn it on by press the power button

7. Set the water discharge

8. Select wash mode

9. Press start button

10. Wait until the washing is finished

11. When it's finished, turn off the machine

12. Unplug the cable

13. Open the top of the machine

14. Take out the clothes from the washing machine

15. Hang clothes under the sun

Flowchart

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The Remaining Money for Groceries

Analysis :

Problem : Algorithm to find the total amount of change for groceries

Requirement :

Input : The number of types of goods purchased, the number of purchases per item, unit price, total of money payment

Process : Calculating the number of change based on the entered data

Output : Total amount of change

Algorithm :

1. Enter the number of types

2. Repeat the steps below for each item :

3. Enter the amount of money payment

4. Find the purchase price (buy_price <-- sum * each)

5. Find the total purchase price (total += buy_price)

6. Find change (change = pay - total)

C++ Program :

#include <iostream>
using namespace std;

struct change{
	string name;
	int sum;
	int each;
}buy[100];

int main (){
	int n, i, pay, change;
	int buy_price[100];
	int total = 0;
	cout<<"Enter the amount of types : ";
	cin>>n;
	cout<<endl;
	for (i=1;i<=n;i++){
		cout<<"Item-"<<i<<" : ";
		cin>>buy[i].name;
		cout<<"Sum of "<<buy[i].name<<" = ";
		cin>>buy[i].sum;
		cout<<"Price per each "<<buy[i].name<<" = ";
		cin>>buy[i].each;
		cout<<endl;
	}
	cout<<"Enter the amount of money payment : ";
	cin>>pay;
	cout<<endl;
	for (i=1;i<=n;i++){
		buy_price[i]=buy[i].sum*buy[i].each;
		cout<<"Price of "<<buy[i].name<<" = "<<buy[i].sum<<" *  		   "<<buy[i].each<<" = "<<buy_price[i];
		cout<<endl;
	}
	cout<<endl;
	for (i=1;i<=n;i++){
		total+=buy_price[i];
	}
	cout<<"Price total = "<<total;
	cout<<endl;
	change=pay-total;
	cout<<"Sum of change = "<<change;
	return 0;
}

Output :